Sizing Round or Octagonal Boxes - Different Size Conductor

Mar 10 / James Stallcup
Stallcup Electrical Education is committed to helping electricians, apprentices, and industry professionals sharpen their skills with a weekly calculation problem based on the National Electrical Code (NEC). Designed to reinforce critical thinking and real-world application, these problems challenge learners to apply NEC principles to electrical design, load calculations, and compliance scenarios. Whether you're preparing for an exam or looking to refine your expertise, Stallcup’s weekly calculation problems provide a valuable learning tool to keep you engaged and up to date with industry standards. Stay ahead of the curve and enhance your electrical knowledge—one calculation at a time! 
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Sizing Round or Octagonal Box Different Size Conductors
Based on the National Electrical Code

Example Problem: What size round or octagon box is required to support a luminaire with 2 - 12-2 w/ ground nonmetallic-sheathed cables (romex) with a fixture stud, two cable clamps, two pigtails, and 2 - 18 AWG fixture wires? (No luminaire canopy)


Step 1: Combination conductors

314.16(B)(1) through (B)(5) and Table 314.16(B)

2 - 12 AWG ungrounded (phase) conductors

2.25 cu. in. x 2 = 4.5 cu. in.

2 - 12 AWG grounded (neutral) conductors

2.25 cu. in. x 2 = 4.5 cu. in.

2 - 12 AWG equipment grounding conductors

2.25 cu. in. x 1 = 2.25 cu. in.

1 fixture stud 

2.25 cu. in. x 1 = 2.25 cu. in.

2 cable clamps

2.25 cu. in. x 1 = 2.25 cu. in.

2 pigtails = 0 cu. in.

2 - 18 AWG fixture wires

1.5 cu. in. x 2 = 3 cu. in.

Total = 18.75 cu. in.


Step 2: Selecting box

Table 314.16(A)

18.75 cu. in. requires 4" x 2-1/8" (100 mm x 54 mm) octagon box


Solution: A 4 in. x 2-1/8 in. (100 mm x 54 mm) octagon box is required.